document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1194493>Question 1194493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this :<BR>\n" );
document.write( "Gordon rode his bike at 15 mph to get his car. He then drove back at 45<BR>\n" );
document.write( "mph. If the entire trip took him 8 hours, how far away was his car?<BR>\n" );
document.write( "Please Include Represent, Relate, Equate, Solve and Prove. Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #826739 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=826739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The ratio of speeds is 15:45 = 1:3, and the distances are the same, so the ratio of times spent at the two speeds is 3:1.<br><BR>\n" );
document.write( "3x = hours spent riding<BR>\n" );
document.write( "x = hours spent driving<br><BR>\n" );
document.write( "3x+x=8<BR>\n" );
document.write( "4x=8<BR>\n" );
document.write( "x=2<br><BR>\n" );
document.write( "hours spent riding at 15mph = 3x = 6<BR>\n" );
document.write( "hours spent driving at 45mph = x = 2<br><BR>\n" );
document.write( "distance riding (rate times time): 6(15) = 90<BR>\n" );
document.write( "distance driving: 2(45) = 90<br><BR>\n" );
document.write( "ANSWER: 90 miles<br><BR>\n" );
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