document.write( "Question 1194518: A rectangular painting is to have a total area (including the frame)
\n" ); document.write( "of 1200 cm2. If the painting is 30 cm long and 20 cm wide, find
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Algebra.Com's Answer #826728 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "x = width of the frame in centimeters.
\n" ); document.write( "This is some positive real number, meaning that x > 0\r
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\n" ); document.write( "\n" ); document.write( "The width of 30 cm bumps up to 30+x+x = 30+2x cm
\n" ); document.write( "This is because we add on two copies of x for either side along the 30 cm dimension.
\n" ); document.write( "The same thing happens with the 20 cm bumping up to 20+2x cm.\r
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\n" ); document.write( "\n" ); document.write( "The painting + frame has dimensions of (30+2x) cm by (20+2x) cm\r
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\n" ); document.write( "\n" ); document.write( "Multiply those dimensions and set the product equal to the stated total area of 1200 sq cm.\r
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\n" ); document.write( "\n" ); document.write( "length*width = area
\n" ); document.write( "(30+2x)*(20+2x) = 1200
\n" ); document.write( "600+60x+40x+4x^2 = 1200
\n" ); document.write( "600+100x+4x^2 = 1200
\n" ); document.write( "4x^2+100x+600-1200 = 0
\n" ); document.write( "4x^2+100x-600 = 0
\n" ); document.write( "4(x^2+25x-150) = 0
\n" ); document.write( "x^2+25x-150 = 0/4
\n" ); document.write( "x^2+25x-150 = 0\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to find x.
\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%2825%29%2B-sqrt%28%2825%29%5E2-4%281%29%28-150%29%29%29%2F%282%281%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-25%2B-sqrt%281225%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-25%2B-++35%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-25%2B35%29%2F%282%29\" or \"x+=+%28-25-35%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810%29%2F%282%29\" or \"x+=+%28-60%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+5\" or \"x+=+-30\"
\n" ); document.write( "Ignore the negative solution. Recall at the top we stated that x > 0.\r
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\n" ); document.write( "\n" ); document.write( "Answer: The width of the frame is 5 cm.
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