document.write( "Question 1194508: How much must be deposited at the end of each month for 3.5 years to accumulate to $1,801.00 at 8%
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Algebra.Com's Answer #826725 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "1 year = 12 months
\n" ); document.write( "3.5*1 year = 3.5*12 months
\n" ); document.write( "3.5 years = 42 months\r
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\n" ); document.write( "\n" ); document.write( "We want the future value to be $1,801 and have it occur at the 42 month mark.
\n" ); document.write( "The annual interest rate in decimal form is r = 0.08\r
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\n" ); document.write( "\n" ); document.write( "Divide by 12 to get the monthly version: r/12 = 0.08/12 = 0.00666666666667
\n" ); document.write( "which is approximate.\r
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\n" ); document.write( "\n" ); document.write( "The future value annuity formula to use is this
\n" ); document.write( "FV = P*( (1+i)^n - 1)/i
\n" ); document.write( "This is an ordinary annuity and not \"annuity due\".
\n" ); document.write( "This is because the deposits happen at the end of each month, rather at the beginning.\r
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\n" ); document.write( "\n" ); document.write( "In this case,
\n" ); document.write( "FV = future value = 1801
\n" ); document.write( "P = unknown monthly deposit
\n" ); document.write( "i = 0.00666666666667 approximately
\n" ); document.write( "n = 42 months\r
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\n" ); document.write( "\n" ); document.write( "Let's solve for P
\n" ); document.write( "FV = P*( (1+i)^n - 1)/i
\n" ); document.write( "1801 = P*( (1+0.00666666666667)^42 - 1)/0.00666666666667
\n" ); document.write( "1801 = P*48.2851385181578
\n" ); document.write( "P = 1801/48.2851385181578
\n" ); document.write( "P = 37.2992613311594
\n" ); document.write( "P = 37.30\r
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\n" ); document.write( "\n" ); document.write( "Answer: $37.30
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