document.write( "Question 1194480: A business owner decides to buy a company car for $53400 and assumes it will have a trade-in value of $21900 after 10 years. The business person uses a constant rate of depreciation (commonly called straight-line depreciation, one of several methods permitted by the IRS) to determine the annual value of the car.\r
\n" ); document.write( "\n" ); document.write( "(a) Find a linear model for the depreciated value V of the car t years after it was purchased?
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\n" ); document.write( "(b) What is the depreciated value of the car after 4 years?
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\n" ); document.write( "\n" ); document.write( "(c) When will the depreciated value fall below $31700? Give an exact answer.
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Algebra.Com's Answer #826714 by Boreal(15235)\"\" \"About 
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year, price
\n" ); document.write( "(0, 53400) and (10, 21900)
\n" ); document.write( "from those ordered pairs the slope is -315.
\n" ); document.write( "point-slope formula y-y1=m(x-x1), y slope and (x1, y1) point
\n" ); document.write( "y-53400=-3150(x)
\n" ); document.write( "or y=-3150x+53400
\n" ); document.write( "after 4 years, x=4 so y=-3150(4)+53400=$40,800
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\n" ); document.write( "31700=-3150x+53400
\n" ); document.write( "so -3150x=-21700
\n" ); document.write( "x=6.89 years but exact is 434/63=62/9 years
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