document.write( "Question 1194493: Please help me solve this :
\n" ); document.write( "Gordon rode his bike at 15 mph to get his car. He then drove back at 45
\n" ); document.write( "mph. If the entire trip took him 8 hours, how far away was his car?
\n" ); document.write( "Please Include Represent, Relate, Equate, Solve and Prove. Thank you very much! \n" ); document.write( "
Algebra.Com's Answer #826698 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
r = rate
\n" ); document.write( "t = time
\n" ); document.write( "d = distance
\n" ); document.write( "formula is r * t = d
\n" ); document.write( "the total time going and coming back is 8 hours.
\n" ); document.write( "for gordon going, the formula becomes 15 * t = d
\n" ); document.write( "for gordon coming back, the formula becomes 45 * (8 - t) = d
\n" ); document.write( "since they both = d, then 15 * t = 45 * (8 - t)
\n" ); document.write( "simplify to get:
\n" ); document.write( "15 * t = 360 - 45 * t
\n" ); document.write( "add 45 * t to both sides of the equation to get:
\n" ); document.write( "60 * t = 360
\n" ); document.write( "solve for t to get:
\n" ); document.write( "t = 6
\n" ); document.write( "the original formulas become:
\n" ); document.write( "15 * 6 = d which becomes 90 = d
\n" ); document.write( "45 * (8 - 6) = d which becomes 45 * 2 = d which becomes 90 = d
\n" ); document.write( "his car is 90 miles away.
\n" ); document.write( "that's your answer.\r
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