document.write( "Question 1194362: Find the vertex, focus, and directrix of the parabola X^2-4X- 4Y +16=0. Solve and graph \n" ); document.write( "
Algebra.Com's Answer #826666 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "preferring all lower case, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "With this, if you compare to (x-h)^2=4p(y-k), then p=1, or the focus and directrix each is 1 unit from the vertex; \n" ); document.write( "and \n" ); document.write( "for your example, \n" ); document.write( "==================================================================== \n" ); document.write( "vertex (2,3) \n" ); document.write( "parabola is with vertical symmetry axis with vertex as minimum; \n" ); document.write( "focus (2,4) \n" ); document.write( "directrix y=2 \n" ); document.write( "==================================================================== \n" ); document.write( " |