document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1194435>Question 1194435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mean useful life of car batteries is 57 months. They have a standard deviation of 6. Assume the useful life of batteries is normally distributed.\r<BR>\n" );
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document.write( "a. Calculate the percent of batteries with a useful life of less than 45 months. (Round your answer to the nearest hundredth percent.)<BR>\n" );
document.write( "b. Calculate the percent of batteries that will last longer than 75 months. (Round your answer to the nearest hundredth percent.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #826641 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=826641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(45-57)/6=-2<BR>\n" );
document.write( "probability z <-2=0.0228 or 2.28%<BR>\n" );
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document.write( "this is z>3 with probability of 0.0013 or 0.13% </SPAN>\n" );
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