Algebra.Com's Answer #826630 by ikleyn(52781)  You can put this solution on YOUR website! . \n" );
document.write( "The numerator of the fraction is x, while the denominator is 5 more the numerator. \n" );
document.write( "if the value of the fraction is less than 2/5, find the value of x \n" );
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document.write( "Let x be the numerator; then the denominator is (x+5) and the fraction is .\r\n" );
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document.write( "They want you solve this inequality\r\n" );
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document.write( " < . (1)\r\n" );
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document.write( " | Attention (!) |\r\n" );
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document.write( " Do not multiply both sides by (x+5), because you don't know in advance, \r\n" );
document.write( " if this value is positive or negative.\r\n" );
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document.write( " | THERE IS ANOTHER METHOD TO SOLVE IT without making wrong steps ! |\r\n" );
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document.write( "Re-write equation (1) equivalently in this form\r\n" );
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document.write( " - < 0.\r\n" );
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document.write( "Write it with the common denominator, which is 5*(x+5).\r\n" );
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document.write( " - < 0.\r\n" );
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document.write( "Simplify\r\n" );
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document.write( " < 0,\r\n" );
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document.write( " < 0,\r\n" );
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document.write( " < 0.\r\n" );
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document.write( "This inequality is equivalent to\r\n" );
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document.write( " < 0.\r\n" );
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document.write( "The last inequality is hold in these two cases:\r\n" );
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document.write( " (a) 3x-10 < 0 and x+5 > 0\r\n" );
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document.write( "or \r\n" );
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document.write( " (b) 3x-10 > 0 and x+5 < 0.\r\n" );
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document.write( "In case (a), it implies 3x < 10 and x > -5, which is the same as x < 10/3 and x > -5,\r\n" );
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document.write( " which gives the answer -5 < x < 10/3.\r\n" );
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document.write( "In case (b), it implies 3x > 10 and x < -5, which has no solutions.\r\n" );
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document.write( "ANSWER. The solution set is -5 < x < 10/3, or, in interval form, (-5, 10/3).\r\n" );
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document.write( "Solved.\r \n" );
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