document.write( "Question 1194377: Math's\r
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document.write( "A jar contains 10 coins: 3 pennies, 2 nickels, 4 dimes, and 1 quarter. Two coins are selected at random from the jar with replacement (the coin is pulled, looked at, then put back in the jar.) Find the probability that a dime is selected first, then a quarter. You should write your answer as a decimal.uld write your answer as a decimal. \n" );
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Algebra.Com's Answer #826573 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are 4 dimes out of 10 coins total. \n" ); document.write( "The probability of picking a dime is 4/10 = 2/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That coin is put back, meaning the original state of the jar has not changed. In turn, it leads to the probability of picking a quarter to be the same as if it was selected first. \n" ); document.write( "If on the other hand the coin wasn't put back, then the probability for the second selection would change. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There is 1 quarter out of 10 coins. \n" ); document.write( "The probability of picking a quarter is 1/10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the two fractions mentioned: \n" ); document.write( "(2/5)*(1/10) = 2/50 = 4/100 = 0.04\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 0.04 \n" ); document.write( " \n" ); document.write( " |