document.write( "Question 1194315: If tan A = ¾ and cos B = 12/13, find
\n" ); document.write( "a. Tan (A - B)
\n" ); document.write( "b. c. tan ( B - A )
\n" ); document.write( "c. Sin ( A + B)
\n" ); document.write( "d. cos 2A
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Algebra.Com's Answer #826500 by Alan3354(69443)\"\" \"About 
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If tan A = ¾ and cos B = 12/13, find
\n" ); document.write( "a. Tan (A - B)
\n" ); document.write( "b. c. tan ( B - A )
\n" ); document.write( "c. Sin ( A + B)
\n" ); document.write( "d. cos 2A
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\n" ); document.write( "tan(A) = 3/4
\n" ); document.write( "tan = y/x
\n" ); document.write( "r = sqrt(x^2 + y^2) = 5
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\n" ); document.write( "sin = y/r
\n" ); document.write( "cos = x/r
\n" ); document.write( "cot = 1/tan
\n" ); document.write( "sec = 1/cos
\n" ); document.write( "csc = 1/sin
\n" ); document.write( "----
\n" ); document.write( "cos(B) = 12/13 = x/r ---> y = 5
\n" ); document.write( "sin = y/r
\n" ); document.write( "cos = x/r
\n" ); document.write( "tan = y/x
\n" ); document.write( "cot = 1/tan
\n" ); document.write( "sec = 1/cos
\n" ); document.write( "csc = 1/sin
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\n" ); document.write( "a. Tan (A - B)
\n" ); document.write( "b. c. tan ( B - A )
\n" ); document.write( "c. Sin ( A + B)
\n" ); document.write( "d. cos 2A
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\n" ); document.write( "Look up formulas at Wikipedia \"Half angle formulas\"
\n" ); document.write( "---- Email via the TY note for help or to check your work.
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