document.write( "Question 1194313: The mean height of women in a country (ages 20−29) is 63.7 inches. A random sample of 70 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume σ=2.91.
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document.write( "Part 1
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document.write( "The probability that the mean height for the sample is greater than 64 inches is enter your response here. \n" );
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Algebra.Com's Answer #826481 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "mu = 63.7 = population mean height \n" ); document.write( "n = 70 = sample size \n" ); document.write( "sigma = 2.91 = population standard deviation of the heights \n" ); document.write( "xbar = sample mean\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We want to know the value of P(xbar > 64)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's find the z score for xbar = 64 \n" ); document.write( "z = (xbar - mu)/(sigma/sqrt(n)) \n" ); document.write( "z = (64 - 63.7)/(2.91/sqrt(70)) \n" ); document.write( "z = 0.86253610982893 \n" ); document.write( "z = 0.86\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a table like this one \n" ); document.write( "https://www.ztable.net/ \n" ); document.write( "to find that \n" ); document.write( "P(Z < 0.86) = 0.80511 \n" ); document.write( "which leads to \n" ); document.write( "P(Z > 0.86) = 1-P(Z < 0.86) \n" ); document.write( "P(Z > 0.86) = 1-0.80511 \n" ); document.write( "P(Z > 0.86) = 0.19489 \n" ); document.write( "which gets us back to \n" ); document.write( "P(xbar > 64) = 0.19489 \n" ); document.write( "You can use a z calculator if you require more accuracy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Approximately 0.19489 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |