document.write( "Question 113571: Find the length and width of a rectangle whose perimeter is 40 feet, and whose area is 96 square feet.\r
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document.write( "I think I have the right equation for the perimeter: P=2l+2w=96 sq ft.
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document.write( "Is this right?\r
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document.write( "I do not know how to set the other equation up or solve it.\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #82644 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the length and width of a rectangle whose perimeter is 40 feet, and whose area is 96 square feet.\r \n" ); document.write( "\n" ); document.write( "I think I have the right equation for the perimeter: P=2l+2w=40 ft. \n" ); document.write( "---------- \n" ); document.write( "Then, divide thru by 2 to get: \n" ); document.write( "l + w = 20 \n" ); document.write( "----------- \n" ); document.write( "If width = w, length = 20-w \n" ); document.write( "---------------- \n" ); document.write( "AREA: \n" ); document.write( "Area = (length)(width) \n" ); document.write( "96 = w(20-w) \n" ); document.write( "96 = 20w-w^2 \n" ); document.write( "----- \n" ); document.write( "w^2 -20w+96 = 0 \n" ); document.write( "(w-8)(w-12)=0 \n" ); document.write( "If w=8 then length = 12 \n" ); document.write( "If w=12 then length = 8 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I do not know how to set the other equation up or solve it.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |