document.write( "Question 1194256: 6 pencils and 5 crayons are 25.7 inches. 7 pencils and 6 crayons are 30.2 inches. Each pencil is the same length as the other pencils, and each crayon is the same length as the other crayons. What is the length of 1 pencil? What is the length of 1 crayon?
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Algebra.Com's Answer #826418 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "The information in this problem makes it easier to solve using a non-standard algebraic method.

\n" ); document.write( "(1) 7p+6c = 30.2
\n" ); document.write( "(2) 6p+5c = 25.7

\n" ); document.write( "Subtract the (2) from (1):

\n" ); document.write( "(3) p+c = 4.5

\n" ); document.write( "Multiply that by 5:

\n" ); document.write( "(4) 5p+5c = 22.5

\n" ); document.write( "Subtract (4) from (2):

\n" ); document.write( "(5) p = 25.7-22.5 = 3.2

\n" ); document.write( "Subtract (5) from (3):

\n" ); document.write( "(6) c = 1.3

\n" ); document.write( "ANSWERS:
\n" ); document.write( "pencil: 3.2 inches
\n" ); document.write( "crayon: 1.3 inches

\n" ); document.write( "Note that formal algebraic solution corresponds to the following solution using common sense:

\n" ); document.write( "7 pencils and 6 crayons have a total length of 30.2 inches
\n" ); document.write( "6 pencils and 5 crayons have a total length of 25.7 inches
\n" ); document.write( "therefore, 1 pencil and 1 crayon have a total length of 30.2-25.7 = 4.5 inches
\n" ); document.write( "therefore, 5 pencils and 5 crayons have a total length of 5*4.5 = 22.5 inches
\n" ); document.write( "therefore, 1 pencil has a length of 25.7-22.5 = 3.2 inches
\n" ); document.write( "therefore, 1 crayon has a length of 4.5-3.2 = 1.3 inches

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