document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1194246>Question 1194246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The central angle corresponding to a circular brake shoe measures 60°. To two decimal places, how long is the curved surface of the brake shoe if the length of the radius is 9 in.?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #826384 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=826384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "Answer: 9.42 inches\r<BR>\n" );
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document.write( "Work Shown:<BR>\n" );
document.write( "x = central angle = 60 degrees<BR>\n" );
document.write( "r = radius = 9 inches<BR>\n" );
document.write( "L = arc length <BR>\n" );
document.write( "L = (x/360)*2*pi*r<BR>\n" );
document.write( "L = (60/360)*2*pi*9<BR>\n" );
document.write( "L = 3*pi<BR>\n" );
document.write( "L = 9.42477796076938<BR>\n" );
document.write( "L = 9.42\r<BR>\n" );
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document.write( "Notes:<BR>\n" );
document.write( "<ul><li>I used the calculator's stored version of pi to get the most accuracy possible. If your teacher requires you to use the approximation pi = 3.14, then be sure to follow those instructions.</li><li>The x/360 portion takes a fractional amount of the circumference C = 2*pi*r; hence the (x/360)*2*pi*r</li></ul><BR>\n" );
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