document.write( "Question 1194213: Find the area in square units
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document.write( "A figure consists of eight sides that are vertical or horizontal. Each pair of adjacent sides meet at a right angle. Starting with the top left corner and traveling clockwise, the sides are as follows.\r
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document.write( "The first side goes right. It is labeled 6.
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document.write( "The second side goes down.
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document.write( "The third side goes right.
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document.write( "The fourth side goes up. It is the same length as the second side.
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document.write( "The fifth side goes right. It is labeled 2.
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document.write( "The sixth side goes down. It is labeled 9.
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document.write( "The seventh side goes left. It is labeled 16. The vertical distance between this side and the third side is labeled 3.
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document.write( "The eighth side goes up and ends where the first side starts. \n" );
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Algebra.Com's Answer #826374 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "The figure is a closed figure; the eighth side ends where the first side starts. \n" ); document.write( "That means the \"rights\" and \"lefts\" must be equal, and the \"ups\" and \"downs\" must be equal. \n" ); document.write( "rights: side 1 (6), side 3 (unknown), and side 5 (2) \n" ); document.write( "lefts: side 7 (16) \n" ); document.write( "6+y+2 = 16 \n" ); document.write( "y=8 \n" ); document.write( "So side 3 has length 8. \n" ); document.write( "ups and downs.... \n" ); document.write( "side 2 (down) and side 4 (up) are the same length, so those cancel each other out. The only other down is side 6 (9), so side 8 (up) is also 9. \n" ); document.write( "The vertical distance between sides 3 and 7 is 3; since side 6 is 9, the length of sides 2 and 4 is 9-3 = 6. \n" ); document.write( "So the figure is a rectangle with sides 16 and 9, with a rectangle with side lengths 6 and 8 removed. \n" ); document.write( "The area of the figure is then (16*9)-(6*8) = 144-48 = 96. \n" ); document.write( "ANSWER: 96 square units \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |