document.write( "Question 1194217: In a triangle of perimeter 72 in., the length of the first side is twice the length of the second side, and the length of the third side is 8 in. more than the length of the second side. Find the lengths of the three sides in inches. \n" ); document.write( "

Algebra.Com's Answer #826358 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "Let the second side length be x;  then first side length is 2x and third side length is (x+8).\r\n" );
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document.write( "From the problem, you have this equation\r\n" );
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document.write( "    x + 2x + (x+8) = 72.\r\n" );
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document.write( "Its solution is  x= 16 cm.\r\n" );
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document.write( "So, first side length is 32 cm; second side length is 16 cm and third side length is 24 cm.\r\n" );
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document.write( "The triangle inequalities are satisfied, so the obtained numbers provide the ANSWER.\r\n" );
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