document.write( "Question 1194192: A boat leaves a dock and travels at the rate of 36 kilometers per hour. Twenty
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document.write( "minutes later a second boat leaves the same dock and travels the same route at 50 kilometers per
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document.write( "hour. How long will it take the second boat to be 5 kilometers behind the first boat? \n" );
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Algebra.Com's Answer #826330 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The first boat travels at 36km/h for 20 minutes (1/3 hour) before the second boat starts, traveling (1/3)*36 = 12km. \n" ); document.write( "In order for the second boat to become 5km behind the first, the second boat has to travel 12-5 = 7km farther than the first. \n" ); document.write( "Related to the familiar formula \n" ); document.write( "(distance) = (rate) times (time) \n" ); document.write( "we have the corresponding formula \n" ); document.write( "(difference in distances) = (difference in rates) times (time) \n" ); document.write( "The difference in distances is 7km, and the difference in speeds is 50-36 = 14km/h, so \n" ); document.write( "7 = (14)*t \n" ); document.write( "t = 7/14 = 1/2 \n" ); document.write( "ANSWER: It will take the second boat 1/2 hour, or 30 minutes, to get to where it is 5km behind the first boat. \n" ); document.write( " \n" ); document.write( " |