document.write( "Question 1194180: If 5x-y is divisible by 4 and 2x+3y is odd. Then 7x+2y is odd for all x,y ∈Z. Prove by direct proof or contrapositive \n" ); document.write( "
Algebra.Com's Answer #826320 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "If 5x-y is divisible by 4, then it's also divisible by 2 since 4 = 2*2\r
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\n" ); document.write( "\n" ); document.write( "Put another way:
\n" ); document.write( "4 is a factor of 5x-y
\n" ); document.write( "5x-y = 4k for some integer k
\n" ); document.write( "5x-y = 2*(2k)
\n" ); document.write( "This shows that 5x-y is even\r
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\n" ); document.write( "\n" ); document.write( "5x-y is even while 2x+3y is odd
\n" ); document.write( "(5x-y)+(2x+3y) = (5x+2x) + (-y+3y) = 7x+2y\r
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\n" ); document.write( "\n" ); document.write( "We've summed an even number (5x-y) with an odd number (2x+3y) to get an odd result (7x+2y). This concludes the proof.\r
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\n" ); document.write( "\n" ); document.write( "Here's a side proof showing that odd+even = odd
\n" ); document.write( "This is something for another page (perhaps a reference page in your notebook somewhere).\r
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\n" ); document.write( "\n" ); document.write( "k = some integer
\n" ); document.write( "2k = some even integer
\n" ); document.write( "2m+1 = some odd integer\r
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\n" ); document.write( "\n" ); document.write( "odd+even = (2m+1)+2k = (2m+2k)+1 = 2(m+k)+1 = some other odd integer\r
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\n" ); document.write( "\n" ); document.write( "This concludes the proof that odd+even = odd
\n" ); document.write( "Since order doesn't matter when it comes to adding, it's the same as saying even+odd = odd\r
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\n" ); document.write( "\n" ); document.write( "Some numeric examples to partially verify the claim:
\n" ); document.write( "3+2 = 5
\n" ); document.write( "7+14 = 21
\n" ); document.write( "19+18 = 37
\n" ); document.write( "These are examples to help see why the proof works. Of course you'd need the proof above to fully confirm the claim.
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