document.write( "Question 1194108: Given: tangents AB and AC to ⊙O
\n" ); document.write( " m∠ACB = 72°
\n" ); document.write( "Find the following in degrees.
\n" ); document.write( "mBC°\r
\n" ); document.write( "\n" ); document.write( "mBDC°\r
\n" ); document.write( "\n" ); document.write( "m∠ABC°\r
\n" ); document.write( "\n" ); document.write( "m∠A°
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Algebra.Com's Answer #826219 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Two tangents to a circle from the same point are congruent. So triangle ABC is isosceles with base angles BCA and CBA and vertex angle A.

\n" ); document.write( "(1) Use that and the fact that the sum of the angles in a triangle is 180 degrees to find the measures of angle A and angle ABC.

\n" ); document.write( "(2) The two tangents cut the 360 degrees of the circle into two parts. If arc BC is x degrees, then the other arc is 360-x degrees.

\n" ); document.write( "Then the measure of angle A is half the difference between the measures of the two arcs:

\n" ); document.write( "\"A+=+%281%2F2%29%28%28360-x%29-x%29\"

\n" ); document.write( "Use that and the measure of angle A that you found in part (1) to find x, which is the degree measure of arc BC.

\n" ); document.write( "(3) It is impossible to find the measure of angle BDC, since point D is nowhere defined.

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