document.write( "Question 1194108: Given: tangents AB and AC to ⊙O
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document.write( " m∠ACB = 72°
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document.write( "Find the following in degrees.
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document.write( "mBC°\r
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document.write( "mBDC°\r
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document.write( "m∠ABC°\r
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document.write( "m∠A° \n" );
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Algebra.Com's Answer #826219 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Two tangents to a circle from the same point are congruent. So triangle ABC is isosceles with base angles BCA and CBA and vertex angle A. \n" ); document.write( "(1) Use that and the fact that the sum of the angles in a triangle is 180 degrees to find the measures of angle A and angle ABC. \n" ); document.write( "(2) The two tangents cut the 360 degrees of the circle into two parts. If arc BC is x degrees, then the other arc is 360-x degrees. \n" ); document.write( "Then the measure of angle A is half the difference between the measures of the two arcs: \n" ); document.write( " \n" ); document.write( "Use that and the measure of angle A that you found in part (1) to find x, which is the degree measure of arc BC. \n" ); document.write( "(3) It is impossible to find the measure of angle BDC, since point D is nowhere defined. \n" ); document.write( " \n" ); document.write( " |