document.write( "Question 1194102: hi can i get the anwser to both questions
\n" );
document.write( "Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour slower than the other​ group, find the rate of each group.
\n" );
document.write( "slower group rate
\n" );
document.write( "faster group rate\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #826210 by Alan3354(69443) You can put this solution on YOUR website! Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour slower than the other​ group, find the rate of each group. \n" ); document.write( "================ \n" ); document.write( "Walking \"toward each other\" is going in opposite directions. \n" ); document.write( "The speeds are added. \n" ); document.write( "----- \n" ); document.write( "The sum of their speeds is 1050/200 hours = 5.25 mi/hr \n" ); document.write( "------- \n" ); document.write( "Sum = 5.25 \n" ); document.write( "Difference = 1.5 \n" ); document.write( "------ \n" ); document.write( "F + S = 5.25 \n" ); document.write( "F - S = 1.5 \n" ); document.write( "================= Add\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |