document.write( "Question 1194102: hi can i get the anwser to both questions
\n" ); document.write( "Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour slower than the other​ group, find the rate of each group.
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Algebra.Com's Answer #826210 by Alan3354(69443)\"\" \"About 
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Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour slower than the other​ group, find the rate of each group.
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\n" ); document.write( "Walking \"toward each other\" is going in opposite directions.
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\n" ); document.write( "The sum of their speeds is 1050/200 hours = 5.25 mi/hr
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\n" ); document.write( "Sum = 5.25
\n" ); document.write( "Difference = 1.5
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\n" ); document.write( "F + S = 5.25
\n" ); document.write( "F - S = 1.5
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