document.write( "Question 113520This question is from textbook Arithmetic and algebra again
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document.write( ": The sum of the digits of a two-digit number is 7. If the digits are reversed, the new number increased by 3 equals 4 times the original number. Find the original number.\r
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document.write( "here is what I have done:\r
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document.write( "original number 10x + y
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document.write( " new number 10y + x\r
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document.write( "x + y = 7\r
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document.write( " 10x + y = 10y + x + 3
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document.write( "10x -x + y -y = 10y -y + x -x + 3
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document.write( " 9x = 9y + 3
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document.write( " x = y + 3\r
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document.write( " x + y = 7
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document.write( " (y+3) + y = 7
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document.write( " 2y + 3 = 7
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document.write( " 2y +3 -3 = 7 -3
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document.write( " 2y = 4
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document.write( " 2y/2 = 4/2
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document.write( " y = 2\r
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document.write( " x + y = 7
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document.write( " 2 + y = 7
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document.write( " 2 -2 + y = 7 -2\r
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document.write( " y = 5
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document.write( " x = 2\r
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document.write( "I get an answer, but it don't check.
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document.write( "Every time I do this problem this my answer or fractional. please help \n" );
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Algebra.Com's Answer #82620 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! here is one more solution to this problem...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let ten's digit be \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The number is = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When the digits are reversed, the new number becomes\r \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "New number increased by 3 = 4 times the original number\r \n" ); document.write( "\n" ); document.write( " (10y + x) + 3 = 4 (10x + y)\r \n" ); document.write( "\n" ); document.write( "or 10y + x + 3 = 40x + 4y\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substituting \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, the number is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "When the digits are reversed, the new number is \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |