document.write( "Question 1194069: A hockey player scores on 18% of his shots.
\n" );
document.write( "a)What is the probability he will score for the first time on his fifth shot?
\n" );
document.write( "b)What is the probability that it will take him fewer than 3 shots to score?
\n" );
document.write( "c)How many shots should he expect to take before scoring?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #826188 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! This would be 0.82^4*0.18=0.0814 \n" ); document.write( "- \n" ); document.write( "for the first shot it would be 0.18 probability to score \n" ); document.write( "for the second shot it would be 0.82*0.18=0.1476, so the answer is the sum or 0.3276 probability \n" ); document.write( "- \n" ); document.write( "the expected number of shots before scoring is 1/p=1/0.18, or 5.56 \n" ); document.write( " |