document.write( "Question 1194079: Halle la ecuación canónica de la hipérbola que tiene sus Focos en (±3,0) y lado recto |𝐿R| = 5 \n" ); document.write( "
Algebra.Com's Answer #826180 by MathLover1(20850)\"\" \"About 
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Find the canonical equation of the hyperbola that has its Foci at (±3,0) and straight side |SS| = 5\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "Foci at (±\"3\",\"0\") =>\"c=3\" \r
\n" ); document.write( "\n" ); document.write( "=> Since, foci is on x-axis, equation of hyperbola is of the form\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Fa%5E2+-+y%5E2%2Fb%5E2=1+\"\r
\n" ); document.write( "\n" ); document.write( "we know that \"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "so far we have \"3%5E2=a%5E2%2Bb%5E2\"=>\"9=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "if given straight side |SS| =\"+5\", means the length of the latus rectum of the hyperbola is \"5\"\r
\n" ); document.write( "\n" ); document.write( "so, \"%282b%5E2%29%2Fa=5\".........solve for \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"%282b%5E2%29=5a\"\r
\n" ); document.write( "\n" ); document.write( "\"a=%282b%5E2%29%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "go to =>\"9=a%5E2%2Bb%5E2\", substitute \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"9=%28%282b%5E2%29%2F5%29%5E2%2Bb%5E2\".......solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"9=%284b%5E4%29%2F25%2Bb%5E2\"
\n" ); document.write( "\"9%2A25=4b%5E4%2B25b%5E2\"
\n" ); document.write( "\"4b%5E4%2B25b%5E2-225=0\"
\n" ); document.write( "\"%28b%5E2+-+5%29+%284+b%5E2+%2B+45%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "=>\"b%5E2+=5\"
\n" ); document.write( "or
\n" ); document.write( " \"b%5E2=+-45%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Since, a is distance, it cant be negative.\r
\n" ); document.write( "\n" ); document.write( "using positive solution. find \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"a=%282%2A5%29%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"a=2\"=>\"a%5E2=4\"\r
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\n" ); document.write( "\n" ); document.write( "and your equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4+-+y%5E2%2F5=1+\"\r
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