document.write( "Question 1194074: Four girls and three boys are seated randomly in a row. Calculate the following probabilities.
\n" ); document.write( "(a) The girls occupy the first three places.
\n" ); document.write( "(b) They are arranged to alternate girl, boy, girl, etc. \r
\n" ); document.write( "\n" ); document.write( "Answers
\n" ); document.write( "(a) 4/35
\n" ); document.write( "(b) 1/35\r
\n" ); document.write( "\n" ); document.write( "Can someone explain the answers? Thank you.\r
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Algebra.Com's Answer #826174 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The solution from the other tutor is one standard way of answering these two questions. You should understand it and be able to use it to solve similar problems.

\n" ); document.write( "Another standard way of solving these problems is to consider the probabilities of filling the seats one at a time under the given constraints.

\n" ); document.write( "(1) girls in first three places...

\n" ); document.write( "first place: 7 people to choose from; 4 are girls --> P = 4/7
\n" ); document.write( "second place: 6 people to choose from; 3 are girls --> P = 3/6
\n" ); document.write( "third place: 5 people to choose from; 2 are girls --> P = 2/5

\n" ); document.write( "P(girls in first three places) = (4/7)(3/6)(2/5) = 4/35

\n" ); document.write( "(2) alternating...

\n" ); document.write( "Obviously a girl must be first, then a boy, and so on. Without showing in words the probabilities for getting the right gender in the right seat...

\n" ); document.write( "P(alternating) = (4/7)(3/6)(3/5)(2/4)(2/3)(1/2)(1/1) = 1/35
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