document.write( "Question 1194074: Four girls and three boys are seated randomly in a row. Calculate the following probabilities.
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document.write( "(a) The girls occupy the first three places.
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document.write( "(b) They are arranged to alternate girl, boy, girl, etc. \r
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document.write( "Answers
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document.write( "(a) 4/35
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document.write( "(b) 1/35\r
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document.write( "Can someone explain the answers? Thank you.\r
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Algebra.Com's Answer #826171 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! Four girls and three boys are seated randomly in a row. Calculate the following probabilities. \n" ); document.write( "(a) The girls occupy the first three places. \n" ); document.write( "(b) They are arranged to alternate girl, boy, girl, etc. \n" ); document.write( "Answers \n" ); document.write( "(a) 4/35 \n" ); document.write( "(b) 1/35 \n" ); document.write( "Can someone explain the answers? Thank you. \n" ); document.write( "~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(a) The total number of all possible different permutations/arrangements, without any constraints, is\r\n" ); document.write( "\r\n" ); document.write( " (4+3)! = 7! = 1*2*3*4*5*6*7.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " If the girls occupy first three position, then the number of all such permutations/arrangements is\r\n" ); document.write( "\r\n" ); document.write( " (4*3*2) * (7-3)! = (4*3*2) * (4*3*2*1).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " The probability under question (a) is the ratio of these numbers\r\n" ); document.write( "\r\n" ); document.write( " P = {{({(4*3*2)*(4*3*2*1))/(1*2*3*4*5*6*7)}}} =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |