document.write( "Question 1194075: At some stops, a certain bus picks up 5 people. At other stops it picks up 2 and at the same time, let’s off 5. There are no other stops than these. It starts it’s run empty and picks up 5 people. At the end, it has 11 people aboard. If the number of stops is greater than 17, what is the least number of stops the bus makes? \n" ); document.write( "
Algebra.Com's Answer #826170 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x = number of stops where the bus picks up 5 people \n" ); document.write( "y = number of stops where the bus picks up 2 people and lets off 5 \n" ); document.write( "At each of the x stops, the number of people on the bus increases by 5. \n" ); document.write( "At each of the y stops, the number of people on the bus decreases by 3. \n" ); document.write( "Then after (x+y) stops the number of people on the bus is 5x-3y. \n" ); document.write( "We are to find the least number of total stops (x+y) greater than 17 for which the number of people left on the bus is 11: \n" ); document.write( " \n" ); document.write( "This is a linear Diophantine equation -- a single equation with two variables, in which the values of the variables are integers. \n" ); document.write( "Here is a standard formal way for solving this kind of equation. \n" ); document.write( "(1) Solve the equation for one of the variables (it doesn't matter which) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Divide by 5, writing the result on the right as quotient plus remainder: \n" ); document.write( " \n" ); document.write( "(2) Find the values of y that make that expression an integer; find the corresponding values of x, and find the value of x+y. We are looking for the smallest value of x+y that is greater than 17. \r\n" ); document.write( " y x=2+(3y+1)/5 x+y\r\n" ); document.write( " ------------------------\r\n" ); document.write( " 3 2+2 = 4 7\r\n" ); document.write( " 8 2+5 = 7 15\r\n" ); document.write( " 13 2+8 = 10 23 \n" ); document.write( "ANSWER: 23 \n" ); document.write( "A note about solving linear Diophantine equations by this method.... \n" ); document.write( "Note that in the table above, the values of x and y (and x+y) form arithmetic sequences. Specifically, the possible y values have a common difference of 5 and the possible x values have a common difference of 3. The \"5\" and \"3\" are because of the equation x=(3y+1)/5. \n" ); document.write( "If you are solving a problem like this and your list of x and/or y values does not form an arithmetic sequence, then some of your calculations are incorrect. \n" ); document.write( "At the same time, knowing that these lists of values form arithmetic sequences allows you to find other solutions without searching for x or y values. For example, in this problem, seeing that the first two possible y values are 3 and 8, you know that the common difference is 5, so the next possible y values are 13, 18, 23, ...; and since the first two possible x values are 4 and 7, you now that the next possible corresponding x values are 10, 13, 16.... \n" ); document.write( " \n" ); document.write( " |