document.write( "Question 1194068: Find the equation of the horizontal hyperbola that has its center at (0,0), its straight side is 6
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Algebra.Com's Answer #826167 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The standard equation for a hyperbola with a horizontal transverse axis is \r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2+-++%28y-k%29%5E2%2Fb%5E2=+1\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( " center at (\"0\",\"0\")=>\"h=0\" and \"k=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Fa%5E2+-++y%5E2%2Fb%5E2=+1\"\r
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\n" ); document.write( "\n" ); document.write( "its straight side is \"6\" units : a latus rectum (literally, “straight side”).
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\n" ); document.write( " the latus rectum of a hyperbola is \"%282b%5E2%29%2Fa\"\r
\n" ); document.write( "\n" ); document.write( "\"%282b%5E2%29%2Fa=6\"\r
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\n" ); document.write( "\n" ); document.write( "its eccentricity is \"e=sqrt%287%29%2F2=c%2Fa+\"=>\"c=sqrt%287%29\" and\"+a=2\"\r
\n" ); document.write( "\n" ); document.write( "substitute \"a\" in latus rectum formula\r
\n" ); document.write( "\n" ); document.write( "\"%282b%5E2%29%2F2=6\"\r
\n" ); document.write( "\n" ); document.write( "\"2b%5E2=12\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=6\"\r
\n" ); document.write( "\n" ); document.write( "then your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4+-++y%5E2%2F6=+1\"\r
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