document.write( "Question 1194067: The vertices of a hyperbola are the points (−3, 2) and (−3, −2) and the length of its conjugate is 6.
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Algebra.Com's Answer #826165 by ikleyn(52803) $\"\"$ $\"About$

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\n" ); document.write( "The vertices of a hyperbola are the points (−3, 2) and (−3, −2) and the length of its conjugate is 6.
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document.write( "From the given info, the center of the hyperbola is the point (-3,0)\r\n" );
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document.write( "and its real axis lies on vertical line x = -3.\r\n" );
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document.write( "    Thus the hyperbola is \"vertical\", opened up and down.  \r\n" );
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document.write( "Real semi-axis length is half the distance between the vertices  a =  =  = 2.\r\n" );
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document.write( "Also, from the given part, the length of its conjugate axis is 6; hence, conjugate semi-axis length is  b = 6/2 = 3.\r\n" );
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document.write( "Now the standard form equation of the hyperbola is\r\n" );
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document.write( "     -  = 1.    ANSWER\r\n" );
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document.write( "                            P L O T\r\n" );
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document.write( "    \r\n" );
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document.write( "                 Hyperbola  -  = 1\r\n" );
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document.write( "In the plot, we can not see the imaginary axis and imaginary semi-axes: they are invisible.  \r\n" );
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document.write( "But we can show the foci.  They are  (,)  and  (,),  where 13 =  +  =  + .\r\n" );
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