document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1194039>Question 1194039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A dog on a leash is tied to the corner of a yard is 10 feet by 8 feet. If the leash is 12 feet long, how much area can the dog access.   <BR>\n" );
document.write( "Please help me with word question.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #826137 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=826137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A dog on a leash is tied to the corner of a yard is 10 feet by 8 feet.<BR>\n" );
document.write( " If the leash is 12 feet long, how much area can the dog access.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Draw this out, find the diagonal of the yard: d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2810%5E2+%2B+8%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2810%5E2+%2B+8%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 12.8ft<BR>\n" );
document.write( "The leash is only 12ft, so there will be small area above an arc where the dog cannot reach<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Divide the dog access area into 3 sections, 2 right triangles and a portion of a  circle.<BR>\n" );
document.write( "Both triangles have a hypotenuse of 12, find the 3rd side of each triangle<BR>\n" );
document.write( "Triangle 1:<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2812%5E2-8%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2812%5E2-8%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 8.94 ft<BR>\n" );
document.write( "find the area<BR>\n" );
document.write( "A1 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >*8.94*8<BR>\n" );
document.write( "A1 = 35.78 sq/ft<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Triangle 2<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2812%5E2-10%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2812%5E2-10%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 6.63 ft<BR>\n" );
document.write( "A2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >*10*6.63<BR>\n" );
document.write( "A2 = 33.17 sq/ft<BR>\n" );
document.write( ":<BR>\n" );
document.write( "If we find the associated angles of these triangles, we can find the angle of the portion the circle for the 3rd area\r<BR>\n" );
document.write( "\n" );
document.write( "Find the angle of the 1st triangle<BR>\n" );
document.write( "Cos(a1) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2F12 ALIGN=MIDDLE  ALT=\"8%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a1 = 48.2 degrees<BR>\n" );
document.write( "Find the angle of the 2nd triangle<BR>\n" );
document.write( "Cos(a2) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%2F12 ALIGN=MIDDLE  ALT=\"10%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a2 = 35.56 degrees<BR>\n" );
document.write( "Find the angle of the arc in the circle<BR>\n" );
document.write( "-----------------math error here!!!-------------------<BR>\n" );
document.write( "90 - 48.2 - 35.5 = 6.3 degrees<BR>\n" );
document.write( "Find the area of the portion of the circle we're interested in<BR>\n" );
document.write( "A3 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6.3%2F360 ALIGN=MIDDLE  ALT=\"6.3%2F360\"   DISABLED_style= \"max-width:90%; height:auto;\" >*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A12%5E2 ALIGN=MIDDLE  ALT=\"pi%2A12%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A3 = 7.9 sq/ft<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the total area the dog can roam<BR>\n" );
document.write( "35.78 + 33.17 + 7.9 = 76.7 sq/ft\r<BR>\n" );
document.write( "\n" );
document.write( "----------------I'm sorry!!!!------------- </SPAN>\n" );
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