document.write( "Question 1193995: In a bolt factory, machines A, B and C 25%,35% and 40% of total outputs respectively. Of the total of their outputs, 5%,4% and 2% are defective bolts respectively. A bolt is drawn at random and is found to be defective. What is the probability that it was manufactured by machines A, B and C? \n" ); document.write( "
Algebra.Com's Answer #826081 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'll be picky at first.... \n" ); document.write( "Each bolt is produced by a single machine. So the probability that a defective bolts was \"manufactured by machines A, B, and C\" is zero. \n" ); document.write( "ANSWER: 0 \n" ); document.write( "------------------------------------------------------------------------- \n" ); document.write( "Now on to answering the question that the problem MEANT to ask.... \n" ); document.write( "To avoid working with multiplication of percentages in decimal form, I would choose a convenient number for the total number of bolts produced and work with the resulting whole numbers. \n" ); document.write( "So suppose the total production is 10,000 bolts. Then... \n" ); document.write( "Production: \n" ); document.write( "A: 25% of 10,000 = 2500 \n" ); document.write( "B: 35% of 10,000 = 3500 \n" ); document.write( "C: 40% of 10,000 = 4000 \n" ); document.write( "Faulty bolts: \n" ); document.write( "A: 5% of 2500 = 125 \n" ); document.write( "B: 4% of 3500 = 140 \n" ); document.write( "C: 2% of 4000 = 80 \n" ); document.write( "Total defective bolts: 125+140+80 = 345 \n" ); document.write( "P(a defective bolt was produced by machine A) = 125/345 \n" ); document.write( "P(a defective bolt was produced by machine B) = 140/345 \n" ); document.write( "P(a defective bolt was produced by machine C) = 80/345 \n" ); document.write( "Simplify the fractions or convert to decimals as desired/required. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |