document.write( "Question 1193995: In a bolt factory, machines A, B and C 25%,35% and 40% of total outputs respectively. Of the total of their outputs, 5%,4% and 2% are defective bolts respectively. A bolt is drawn at random and is found to be defective. What is the probability that it was manufactured by machines A, B and C? \n" ); document.write( "
Algebra.Com's Answer #826081 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "I'll be picky at first....

\n" ); document.write( "Each bolt is produced by a single machine. So the probability that a defective bolts was \"manufactured by machines A, B, and C\" is zero.

\n" ); document.write( "ANSWER: 0

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\n" ); document.write( "Now on to answering the question that the problem MEANT to ask....

\n" ); document.write( "To avoid working with multiplication of percentages in decimal form, I would choose a convenient number for the total number of bolts produced and work with the resulting whole numbers.

\n" ); document.write( "So suppose the total production is 10,000 bolts. Then...

\n" ); document.write( "Production:
\n" ); document.write( "A: 25% of 10,000 = 2500
\n" ); document.write( "B: 35% of 10,000 = 3500
\n" ); document.write( "C: 40% of 10,000 = 4000

\n" ); document.write( "Faulty bolts:
\n" ); document.write( "A: 5% of 2500 = 125
\n" ); document.write( "B: 4% of 3500 = 140
\n" ); document.write( "C: 2% of 4000 = 80

\n" ); document.write( "Total defective bolts: 125+140+80 = 345

\n" ); document.write( "P(a defective bolt was produced by machine A) = 125/345
\n" ); document.write( "P(a defective bolt was produced by machine B) = 140/345
\n" ); document.write( "P(a defective bolt was produced by machine C) = 80/345

\n" ); document.write( "Simplify the fractions or convert to decimals as desired/required.
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