document.write( "Question 1193984: Club members are going to elect their officers. If there are four candidates for
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document.write( "president, 3 for vice president, and 2 for secretary, then how many ways can the
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document.write( "officers be elected? \n" );
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Algebra.Com's Answer #826065 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reason: \n" ); document.write( "Multiply the values given \n" ); document.write( "4*3*2 = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Why does this work? \n" ); document.write( "Well let's consider just the president and VP for now. \n" ); document.write( "We have 4 people for president and 3 for VP. \n" ); document.write( "Make a table with 4 rows and 3 columns. \n" ); document.write( "The rows correspond to the candidates for president, while the columns are for VP. \n" ); document.write( "This table has 4*3 = 12 inner cells to show the twelve different president/VP combos.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To further extend this thought exercise, now consider a table with 12 rows and 2 columns. \n" ); document.write( "The rows represent all the possible president/VP combos covered in the previous paragraph. \n" ); document.write( "The columns represent the different possibilities for secretary. \n" ); document.write( "This second table has 12*2 = 24 different cells. Each of the 24 cells shows a different combo of president/VP/secretary.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can rewrite 12*2 = 24 into 4*3*2 = 24 to see why we multiply the values. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: Optionally you could create a tree diagram to help see all the possible outcomes. \n" ); document.write( " \n" ); document.write( " |