document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193846>Question 1193846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angle C is the right angle. In right △ABC, m∠B = 30°. Also, AB = 16 radical 3<BR>\n" );
document.write( " and AD bisects ∠BAC<BR>\n" );
document.write( "Find BD </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #826042 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=826042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw this<BR>\n" );
document.write( "AB is 16 sqrt(3), the hypotenuse.<BR>\n" );
document.write( "In this 30-60-90 rt triangle, AC is therefore 8 sqrt(3), half the hypotenuse.<BR>\n" );
document.write( "That makes BC 16<BR>\n" );
document.write( "so BD is 8<BR>\n" );
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document.write( "Also, triangle ACD has a 30 degree angle with adjacent side 8 sqrt(3). That makes the opposite side 8 sqrt(3)/sqrt(3) or 8. </SPAN>\n" );
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