document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193907>Question 1193907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3-78.Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are uniformly distributed with values 0.15, 0.16. 0.17, 0.18, and 0.19. Determine the mean and variance of the coating thickness for this process  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #826039 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=826039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean is the middle of this uniform function that has a=0.15 and b=0.19, so that is (a+b)/2=0.17<BR>\n" );
document.write( "the variance is (b-a)^2/12<BR>\n" );
document.write( "=0.04^2/12=0.0001333 </SPAN>\n" );
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