document.write( "Question 1193971: Make K the subject in the equation
\n" ); document.write( "T = square root of (2Ksq / 0.5S-K)
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Algebra.Com's Answer #826038 by Alan3354(69443)\"\" \"About 
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Make K the subject in the equation
\n" ); document.write( "T = square root of (2Ksq / 0.5S-K)
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\n" ); document.write( "\"T+=+sqrt%282K%5E2%2F%280.5S+-+K%29%29\"
\n" ); document.write( "\"T%5E2+=+2K%5E2%2F%280.5S+-+K%29\"
\n" ); document.write( "\"T%5E2%2A%280.5S+-+K%29+=+2K%5E2\"
\n" ); document.write( "\"0.5S%2AT%5E2+-+T%5E2%2AK+=+2K%5E2\"
\n" ); document.write( "\"2K%5E2+%2B+K%2AT%5E2+-+0.5S%2AT%5E2+=+0\"
\n" ); document.write( "------
\n" ); document.write( "Solve the quadratic:
\n" ); document.write( "\"K+=+-T%5E2%2F4+%2B+sqrt%28T%5E4+%2B+4S%2AT%5E2%29%2F4\"
\n" ); document.write( "\"K+=+-T%5E2%2F4+%2B+T%2Asqrt%28T%5E2+%2B+4S%29%2F4\"
\n" ); document.write( "\"K+=+-T%5E2%2F4+-+T%2Asqrt%28T%5E2+%2B+4S%29%2F4\"\r
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