Algebra.Com's Answer #826007 by ikleyn(52777)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "if an angle θ is a principal angle that lies in the quadrant 3 such that 0 degrees ≤ θ ≤ 360 degrees,
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document.write( "determine the exact value of x, y and r for tan θ= 2/3 and draw the diagram\r
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document.write( "I got for x=3 y=2 and r= square root of 13 not sure how to draw it though
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document.write( "Thanks
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document.write( " =  =  .\r\n" );
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document.write( "So, if the angle  is in Quadrant I, then you can take x = 3, y = 2.\r\n" );
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document.write( "But since the angle is in Quadrant III ( ! given !), you must take x= -3 and y= -2.\r\n" );
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document.write( "So, your point is, actually, (x,y) = (-3,-2).\r\n" );
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document.write( "Thus, from the origin, you should move 3 units left to get x= -3, and then move 2 units down to get y= -2.\r\n" );
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document.write( "This point will be that you should mark on coordinate plane.\r\n" );
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document.write( "Do as instructed, and you will get your sough point.\r\n" );
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document.write( "Solved, explained and completed.\r
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