document.write( "Question 113520This question is from textbook Arithmetic and algebra again
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document.write( ": The sum of the digits of a two-digit number is 7. If the digits are reversed, the new number increased by 3 equals 4 times the original number. Find the original number.\r
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document.write( "here is what I have done:\r
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document.write( "original number 10x + y
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document.write( " new number 10y + x\r
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document.write( "x + y = 7\r
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document.write( " 10x + y = 10y + x + 3
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document.write( "10x -x + y -y = 10y -y + x -x + 3
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document.write( " 9x = 9y + 3
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document.write( " x = y + 3\r
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document.write( " x + y = 7
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document.write( " (y+3) + y = 7
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document.write( " 2y + 3 = 7
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document.write( " 2y +3 -3 = 7 -3
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document.write( " 2y = 4
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document.write( " 2y/2 = 4/2
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document.write( " y = 2\r
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document.write( " x + y = 7
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document.write( " 2 + y = 7
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document.write( " 2 -2 + y = 7 -2\r
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document.write( " y = 5
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document.write( " x = 2\r
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document.write( "I get an answer, but it don't check.
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document.write( "Every time I do this problem this my answer or fractional. please help \n" );
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Algebra.Com's Answer #82598 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Your analysis is correct and you're on the right track. \n" ); document.write( "You made a mistake at this point.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "The new number (digits reversed) increased by 3 equals 4 times the original number. \n" ); document.write( "You forgot the 4. \n" ); document.write( " \n" ); document.write( "Now together with \n" ); document.write( " \n" ); document.write( "should get you a quick answer. \n" ); document.write( "Good luck. \n" ); document.write( "Post another question if you get stuck. \n" ); document.write( " \n" ); document.write( " |