document.write( "Question 113520This question is from textbook Arithmetic and algebra again
\n" ); document.write( ": The sum of the digits of a two-digit number is 7. If the digits are reversed, the new number increased by 3 equals 4 times the original number. Find the original number.\r
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\n" ); document.write( "\n" ); document.write( "here is what I have done:\r
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\n" ); document.write( "original number 10x + y
\n" ); document.write( " new number 10y + x\r
\n" ); document.write( "\n" ); document.write( "x + y = 7\r
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\n" ); document.write( " 10x + y = 10y + x + 3
\n" ); document.write( "10x -x + y -y = 10y -y + x -x + 3
\n" ); document.write( " 9x = 9y + 3
\n" ); document.write( " x = y + 3\r
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\n" ); document.write( " x + y = 7
\n" ); document.write( " (y+3) + y = 7
\n" ); document.write( " 2y + 3 = 7
\n" ); document.write( " 2y +3 -3 = 7 -3
\n" ); document.write( " 2y = 4
\n" ); document.write( " 2y/2 = 4/2
\n" ); document.write( " y = 2\r
\n" ); document.write( "\n" ); document.write( " x + y = 7
\n" ); document.write( " 2 + y = 7
\n" ); document.write( " 2 -2 + y = 7 -2\r
\n" ); document.write( "\n" ); document.write( " y = 5
\n" ); document.write( " x = 2\r
\n" ); document.write( "\n" ); document.write( "I get an answer, but it don't check.
\n" ); document.write( "Every time I do this problem this my answer or fractional. please help
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Algebra.Com's Answer #82598 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Your analysis is correct and you're on the right track.
\n" ); document.write( "You made a mistake at this point.\r
\n" ); document.write( "\n" ); document.write( "\"+++10x+%2B+y+=+10y+%2B+x+%2B+3\"
\n" ); document.write( "The new number (digits reversed) increased by 3 equals 4 times the original number.
\n" ); document.write( "You forgot the 4.
\n" ); document.write( "\"+++highlight%284%29%2810x+%2B+y%29+=+10y+%2B+x+%2B+3\"
\n" ); document.write( "Now together with
\n" ); document.write( "\"x%2By=7\"
\n" ); document.write( "should get you a quick answer.
\n" ); document.write( "Good luck.
\n" ); document.write( "Post another question if you get stuck.
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