document.write( "Question 1193916: How many different four-digit numbers are possible if each digit of the number is either 0,1,2,3,4 or 5, and numbers starting with 3 cannot be even?\r
\n" ); document.write( "\n" ); document.write( "The textbook answer is 972.\r
\n" ); document.write( "\n" ); document.write( "Can someone tell me how to solve this problem?
\n" ); document.write( "

Algebra.Com's Answer #825978 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The first digit can't be 0; and there are special requirements if the first digit is 3. So consider two cases -- first digit 1, 2, 4, or 5; or first digit 3.

\n" ); document.write( "(1) first digit 1, 2, 4, or 5

\n" ); document.write( "There are 4 choices for that first digit, then there are no restrictions for the other digits; so the number of 4-digit numbers with first digit 1, 2, 4, or 5 is 4*6*6*6=864.

\n" ); document.write( "(2) first digit 3

\n" ); document.write( "The first digit has to be 3 (1 choice); the last digit must be odd (1, 3, or 5 -- 3 choices); and there are no restrictions on the other two digits. The number of possible 4-digit even numbers with first digit 3 is 1*3*6*6=108.

\n" ); document.write( "The total number of 4-digit numbers with the given requirements is 864+108=972.

\n" ); document.write( "-----------------------------------------------------------------------

\n" ); document.write( "A comment for tutor @ikleyn, whose math is nearly always very good but whose English is often not....

\n" ); document.write( "There is nothing deficient in the statement of the problem. It says that \"each digit of the number is either 0,1,2,3,4 or 5\". That means repetition of digits is allowed.

\n" ); document.write( "
\n" ); document.write( "
\n" );