document.write( "Question 1193917: Lucinda goes to the local pizzeria for dinner with a group of friends. The menu offers 4 types of soup, 5 main meals, 6 desserts and 3 different types of drinks. Lucinda will order 2 different courses and a drink. How many dinner options does she have?\r
\n" ); document.write( "\n" ); document.write( "Textbook answer is 222.\r
\n" ); document.write( "\n" ); document.write( "Can someone explain the solution of this problem?\r
\n" ); document.write( "\n" ); document.write( "I thought of
\n" ); document.write( "4*5*6 = 120 (for the first course)
\n" ); document.write( "3*4*5 = 60 (for the second course)
\n" ); document.write( "then i add them up to 180 and multiply it by 3 to get 540.
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Algebra.Com's Answer #825975 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "(1) The textbook answer you show doesn't make any sense. Are you looking at the answer for a different problem?

\n" ); document.write( "(2) The statement of the problem is deficient -- it doesn't define what a \"course\" is. Even if we assume that a \"course\" is a soup, a main meal, a dessert, and a drink, it is possible that the two different courses might contain, for example, the same soup.

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