document.write( "Question 1193910: Christian is twice as old as Taskie while Dark is 24 years younger than Christian. If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, how old are these three boys? \n" ); document.write( "
Algebra.Com's Answer #825960 by josgarithmetic(39617)\"\" \"About 
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document.write( "Christian          2t\r\n" );
document.write( "Taskie             t\r\n" );
document.write( "Dark               2t-24\r\n" );
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\n" ); document.write( "If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, \"%282t-6%29%2F2=-3%2B%281%2F2%29%28%28t%2B4%29%2B%282t-24%29%29\"
\n" ); document.write( "the description as an equation\r
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\n" ); document.write( "\n" ); document.write( "Solve the equation and evaluate Christian's age and Dark's age.\r
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\n" ); document.write( "\n" ); document.write( "\"t-3=-3%2B%281%2F2%29%28t%2B4%2B2t-24%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t-3=-3%2B%281%2F2%29%283t-20%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t=%281%2F2%29%283t-20%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2t=3t-20\"\r
\n" ); document.write( "\n" ); document.write( "\"-t=-20\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28t=20%29\"----------now find the other two values.
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