document.write( "Question 1193910: Christian is twice as old as Taskie while Dark is 24 years younger than Christian. If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, how old are these three boys? \n" ); document.write( "
Algebra.Com's Answer #825960 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Christian 2t\r\n" ); document.write( "Taskie t\r\n" ); document.write( "Dark 2t-24\r\n" ); document.write( " \n" ); document.write( "If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, \n" ); document.write( "the description as an equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the equation and evaluate Christian's age and Dark's age.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |