document.write( "Question 1193904: Let u=−3i+j+k and v=mj+nk, where m, n∈ . Given that v is a unit vector perpendicular to u, find the possible values of m and of n. \n" ); document.write( "
Algebra.Com's Answer #825953 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Let u=−3i+j+k and v=mj+nk, where m, n∈ . \n" ); document.write( "Given that v is a unit vector perpendicular to u, find the possible values of m and of n. \n" ); document.write( "~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Since vectors u and v are perpendicular, their scalar product is zero.\r\n" ); document.write( "\r\n" ); document.write( "It gives first equation\r\n" ); document.write( "\r\n" ); document.write( " m + n = 0. (1)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Since vector v has the length of 1, it gives you second equation\r\n" ); document.write( "\r\n" ); document.write( " m^2 + n^2 = 1. (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From (1), express m = -n and substitute into (2). You will get\r\n" ); document.write( "\r\n" ); document.write( " (-n)^2 + n^2 = 1\r\n" ); document.write( "\r\n" ); document.write( " 2n^2 = 1\r\n" ); document.write( "\r\n" ); document.write( " n = +/-\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |