document.write( "Question 1193895: A theater group made appearances in two cities. The hotel charge before tax in the second city was
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Algebra.Com's Answer #825933 by ikleyn(52887) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "A theater group made appearances in two cities.
\n" ); document.write( "The hotel charge before tax in the second city was $1000 lower than in the first.
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\n" ); document.write( "The total hotel tax paid for the two cities was $397.50
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document.write( "x = how much the hotel charges in the first city before tax;\r\n" );
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document.write( "y = how much the hotel charges in the second city before tax.\r\n" );
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document.write( "From the problem, you have these two equations for unknown x and y\r\n" );
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document.write( "        x -     y = 1000       dollars\r\n" );
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document.write( "    0.04x + 0.09y = 397.50     dollars\r\n" );
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document.write( "From first equation, express  x = y + 1000  and substitute to the second equation. You will get\r\n" );
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document.write( "    0.04*(y+1000) + 0.09y = 397.50\r\n" );
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document.write( "Simplify and find y\r\n" );
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document.write( "    0.04y + 40 + 0.09y = 397.50\r\n" );
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document.write( "            0.13y      = 397.50 - 40\r\n" );
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document.write( "                y      =  = 2750.\r\n" );
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document.write( "ANSWER.  2750+1000 = 3750 dollars in the first city and 2750 dollars in the second city.\r\n" );
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