document.write( "Question 1193785: Given: isosceles trapezoid MNPQ with QP = 18 and m∠M = 120°
\n" ); document.write( "the bisectors of ∠s MQP and NPQ meet at point T on MN
\n" ); document.write( "Find: the perimeter of MNPQ
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Algebra.Com's Answer #825821 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "QT bisects angle MQP and PT bisects angle NPQ; angles MQP and NPQ are each 60 degrees, so angles PQT and TPQ are each 30 degrees. So triangle PTQ is isosceles, with base angles 30 degrees.

\n" ); document.write( "TU is the altitude of triangle PTQ; it divides triangle PTQ into congruent 30-60-90 right triangles PTU and QTU. Since QP is 18, PU and QU are each 9.

\n" ); document.write( "PU with length 9 is the long leg of a 30-60-90 right triangle, so TU is 9/sqrt(3) = 3*sqrt(3), and PT is twice TU or 6*sqrt(3).

\n" ); document.write( "Angle MNP is 120 degrees, so angle NPQ is 60 degrees; PT bisects angle NPQ, so angle NPT is 30 degrees; since angle MNP is 120 degrees, triangle TNP is also isosceles with base angles 30 degrees.

\n" ); document.write( "Altitude NV of triangle TNP divides triangle TNP into two congruent 30-60-90 right triangles, each with long leg equal to half of TP, which is 3*sqrt(3). So in triangle TVN NV is 3 and TN is 6.

\n" ); document.write( "Then triangles QMT and PNT are both isosceles with legs of length 6, and the perimeter of trapezoid MNPQ is 6+6+9+9+6+6 = 42.

\n" ); document.write( "ANSWER: 42

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