document.write( "Question 1193722: A low grade of oil contains 2.5% of an additive and a high grade of oil contains 7.5% of an additive. How many liters of the 7.5% additive oil must be added to 500 L of the 2.5% additive oil to get a mixture with 6.5% of the additive? \n" ); document.write( "
Algebra.Com's Answer #825755 by josgarithmetic(39617)\"\" \"About 
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500 L of 2.5% additive
\n" ); document.write( "x Liters of the 7.5% additive
\n" ); document.write( "Mixture result 6.5% additive\r
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\n" ); document.write( "\n" ); document.write( "Account for the amount of the pure additive.
\n" ); document.write( "\"2.5%2A500%2B7.5x=6.5%28x%2B500%29\"
\n" ); document.write( "Solve!\r
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\n" ); document.write( "\n" ); document.write( "Do all computations LAST.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"7.5x%2B2.5%2A500=6.5x%2B6.5%2A500\"
\n" ); document.write( "\"7.5x-6.5x=6.5%2A500-2.5%2A500\"\r
\n" ); document.write( "\n" ); document.write( "\"%287.5-6.5%29x=500%286.5-2.5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28x=500%28%286.5-2.5%29%2F%287.5-6.5%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=500%284%2F1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=2000%29\"\r
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\n" ); document.write( "\n" ); document.write( "CHECK - Does this value work?\r
\n" ); document.write( "\n" ); document.write( "\"2.5%2A500%2B7.5%2A2000=6.5%282500%29\"
\n" ); document.write( "\"1250%2B15000=16250\"
\n" ); document.write( "\"16250=16250\"
\n" ); document.write( "YES
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\n" );