document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193721>Question 1193721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the total surface area of the walls of a hospital ward 5m long, 4m wide and 2.5m high.<BR>\n" );
document.write( "B)One litre of paint covers 15m^2. How many litres of paint will be needed to paint the inside wall?  </SPAN>\n" );
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document.write( "Answer: <font color=red>3 liters of paint</font>\r<BR>\n" );
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document.write( "Reason:\r<BR>\n" );
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document.write( "Refer to this post<BR>\n" );
document.write( "<a  rel=nofollow HREF= \"https://www.algebra.com/algebra/homework/Surface-area/Surface-area.faq.question.1193720.html\">https://www.algebra.com/algebra/homework/Surface-area/Surface-area.faq.question.1193720.html</a><BR>\n" );
document.write( "where I detail how to find the surface area of the walls. The summary is that the total wall surface area is 45 square meters.\r<BR>\n" );
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document.write( "Since one liter of paint covers 15 square meters, this means we need <font color=red>3 liters of paint</font> to cover 45 square meters.\r<BR>\n" );
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document.write( "Think of it like the ratio<BR>\n" );
document.write( "1 liter: 15 m^2<BR>\n" );
document.write( "3*1 liter: 3*15 m^2<BR>\n" );
document.write( "<font color=red>3 liters</font>: 45 m^2\r<BR>\n" );
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document.write( "Or you could solve it using a proportion<BR>\n" );
document.write( "(1 liter)/(15 m^2) = (x liters)/(45 m^2)<BR>\n" );
document.write( "1/15 = x/45<BR>\n" );
document.write( "1*45 = 15*x ... cross multiplying here<BR>\n" );
document.write( "45 = 15x<BR>\n" );
document.write( "15x = 45<BR>\n" );
document.write( "x = 45/15<BR>\n" );
document.write( "x = <font color=red>3 liters of paint are needed</font><BR>\n" );
document.write( "There are other ways to solve the proportion, and not to mention other pathways, so you have a few options to pick from.<BR>\n" );
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