document.write( "Question 1193720: What is the total surface area of the walls of a hospital ward 5m long, 4m wide and 2.5m high.
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Algebra.Com's Answer #825752 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 45 square meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown: \n" ); document.write( "L = 5 = length \n" ); document.write( "W = 4 = width \n" ); document.write( "H = 2.5 = height \n" ); document.write( "SA = total surface area of all walls + floor + ceiling \n" ); document.write( "SA = 2*(LW + LH + WH) \n" ); document.write( "SA = 2*(5*4 + 5*2.5 + 4*2.5) \n" ); document.write( "SA = 85 \n" ); document.write( "LSA = lateral surface area = area of the walls only (i.e exclude the floor and ceiling) \n" ); document.write( "LSA = SA - (floor area) - (ceiling area) \n" ); document.write( "LSA = 85 - (5*4) - (5*4) \n" ); document.write( "LSA = 85 - 20 - 20 \n" ); document.write( "LSA = 45 square meters is the area of all the walls only.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another approach: \n" ); document.write( "The perimeter of the rectangular floor is 2*(L+W) = 2*(5+4) = 18 meters. Multiply this with the height to get 18*2.5 = 45 square meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yet another approach: \n" ); document.write( "The 5 by 2.5 walls are 5*2.5 = 12.5 sq meters each. So far that accounts for 12.5+12.5 = 25 square meters of wall area. \n" ); document.write( "The 4 by 2.5 walls have area of 4*2.5 = 10 square meters each, subtotaling 10+10 = 20 additional square meters of wall. \n" ); document.write( "The total wall area is 25+20 = 45 square meters \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |