document.write( "Question 1193708: Three times the least of three consecutive odd integers exceeds twice the greatest by 19. Find the three integers. \n" ); document.write( "

Algebra.Com's Answer #825747 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Three times the least of three consecutive odd integers exceeds twice the greatest by 19. Find the three integers.
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document.write( "Let the three consecutive integer numbers be n, (n+2) and (n+4).\r\n" );
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document.write( "Then your equation to find \"n\" is\r\n" );
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document.write( "    3*n = 2*(n+4) + 19.\r\n" );
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document.write( "Now simplify it and find \"n\"\r\n" );
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document.write( "    3n = 2n + 8 + 19\r\n" );
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document.write( "    3n - 2n = 8 + 19\r\n" );
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document.write( "       n    =   27.\r\n" );
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document.write( "ANSWER.  The numbers are  27, 29 and 31.\r\n" );
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