document.write( "Question 1193693: Sierra went on a 200 mile trip to a soccer game. On the way back, due to road construction she had to drive 10 miles per hour slower. This made the trip take 1 hour longer. How fast did she drive to the soccer game? \n" ); document.write( "
Algebra.Com's Answer #825728 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Basic idea is RT=D for R rate or speed, time T, and distance D.\r
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\n" ); document.write( "\"RT=D\"\r
\n" ); document.write( "\n" ); document.write( "\"%28RT%29%2FR=D%2FR\"\r
\n" ); document.write( "\n" ); document.write( "\"T=D%2FR\"\r
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\n" ); document.write( "\n" ); document.write( "Your given example allows you to form two expressions of time, and question asks for their difference.\r
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document.write( "                SPEEDS        TIMES              DISTANCE\r\n" );
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document.write( "GOING TO        r              200/r                200\r\n" );
document.write( "RETURN          r-10           200/(r-10)           200\r\n" );
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document.write( "DIFF.                            1\r\n" );
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\n" ); document.write( "With that you can setup \"200%2F%28r-10%29-200%2Fr=1\" , and then simplify and solve.
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