document.write( "Question 1193669: Each of two groups consists of 100 patients who have leukaemia. A new drug is given to the first group but not to the second (the control group). It is found that in the first group 60 people have remission for 2 years; but only 40 in the second group. Find 95% CI. \n" ); document.write( "
Algebra.Com's Answer #825719 by Boreal(15235)\"\" \"About 
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two sample proportion 95% half-interval is z*SE
\n" ); document.write( "SE: start with group 1 SE which is sqrt(0.6*0.4/100) or 0.0490, and group 2 SE which is the same
\n" ); document.write( "the SE is sqrt(0.0490^2+0.0490^2)=0.0693
\n" ); document.write( "z*SE=1.96*0.0693=0.1358
\n" ); document.write( "the actual 95%CI is the difference +/- SE which is (0.0642, 0.3358). We are looking at the difference in proportion of survival between 1 and 2.
\n" ); document.write( "This is consistent with the highly significant difference.
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