document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113480>Question 113480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help.\r<BR>\n" );
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document.write( "A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. <BR>\n" );
document.write( "The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. \r<BR>\n" );
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document.write( "How much of each type of bean should be used in the mixture?\r<BR>\n" );
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document.write( "Please show the equations used for the solution.\r<BR>\n" );
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document.write( "Thanks<BR>\n" );
document.write( "JMS\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82570 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9X+12(100-X)=100*11.25<BR>\n" );
document.write( "9X+1200-12X=1125<BR>\n" );
document.write( "-3X=1125-1200<BR>\n" );
document.write( "-3X=-75<BR>\n" );
document.write( "X=-75/-3<BR>\n" );
document.write( "X=25 ANSWER. FOR THE POUNDS OF $9 COFFEE USED.<BR>\n" );
document.write( "100-25=75 FOR THE POUNDS OF $12 COFFEE USED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "9*25+12*75=100*11.25<BR>\n" );
document.write( "225+900=1125<BR>\n" );
document.write( "1125=1125\r<BR>\n" );
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