document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1193648>Question 1193648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist mixes water (containing no salt) with a solution that contains 55% salt. She wants to obtain 220 ounces of a mixture that is 30% salt. How many ounces of water and how many ounces of the 55% salt solution should she use?\r<BR>\n" );
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document.write( "Water=   Ounces<BR>\n" );
document.write( "Salt Solution=    Ounces </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #825698 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=825698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Ignore the fact that a 30% or 55% salt solution is not physically possible.  This is a math problem for giving the student practice in solving mixture problems.<br><BR>\n" );
document.write( "The formal algebraic solution provided by the other tutor uses a good traditional method.<br><BR>\n" );
document.write( "Here is a quick informal way to solve any 2-part mixture problem like this.<br><BR>\n" );
document.write( "Think of this as starting with a 55% solution and adding a 0% solution to obtain a 30% solution.  The percentage of the mixture starts at 55% and moves towards 0%, stopping when it reaches 30%.<br><BR>\n" );
document.write( "30% is 5/11 of the way from 55% to 0%.  (55 to 0 is a change of 55; 55 to 30 is a change of 25; 25/55 = 5/11.)<br><BR>\n" );
document.write( "That means 5/11 of the mixture is the 0% solution (water) that she is adding.<br><BR>\n" );
document.write( "So the amount of water to be added to make 220 ounces of the mixture is 5/11 of 220 ounces, which is 100 ounces.  So then the number of ounces of 55% solution she needs is 220-100 = 120.<br><BR>\n" );
document.write( "ANSWER: 120 ounces of the 55% solution; 100 ounces of water.<br><BR>\n" );
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